QQuestionChemistry
QuestionChemistry
The molecule XeF^2 does not obey the octet rule.
Draw its Lewis structure.
State the type of octet-rule exception.
Include lone pair electrons in the Lewis structure.
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Answer
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Step 1I'll solve this problem step by step, following the specified LaTeX and formatting guidelines:
Step 2: Determine the total number of valence electrons
- Total valence electrons: $$8 + 14 = 22$$ electrons
- Xe (Xenon): 8 valence electrons - F (Fluorine): 7 valence electrons × 2 = 14 valence electrons
Final Answer
- Lewis structure shows Xe with 12 electrons - Octet rule exception: Expanded valence shell - Central Xe atom has 3 lone pairs and 2 single bonds
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