QQuestionChemistry
QuestionChemistry
"There are many Lewis structures you could draw for sulfuric acid, H^2SO^4 (each H is bonded to an O).
Part A: What Lewis structure(2$) would you draw to satisfy the octet rule?
Draw the molecule(2$) by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons."
6 months agoReport content
Answer
Full Solution Locked
Sign in to view the complete step-by-step solution and unlock all study resources.
Step 1: Identify the number of valence electrons for each atom in H^2SO^4.
- Hydrogen (H): 1 valence electron - Sulfur (S): 6 valence electrons - Oxygen (O): 6 valence electrons
Step 2: Calculate the total number of valence electrons in the molecule.
- Total valence electrons = (2 * number of Hydrogen atoms) + 6 (Sulfur atom) + (4 * Oxygen atoms) - Total valence electrons = (2 * 2) + 6 + (4 * 4) = 4 + 6 + 16 = 26 valence electrons
Final Answer
The Lewis structure for H^2SO^4 is shown above, with all atoms satisfying the octet rule and all lone pairs of electrons included.
Need Help with Homework?
Stuck on a difficult problem? We've got you covered:
- Post your question or upload an image
- Get instant step-by-step solutions
- Learn from our AI and community of students