QQuestionChemistry
QuestionChemistry
What is the molecular geometry and Lewis structure of IF^−2(1)?
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Answer
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Step 1**Step 1:** Determine the total number of valence electrons in an IF$^-$ ion.
- Iodine (I) is in the 7th group of the periodic table, so it has 7 valence electrons. - Fluorine (F) is in the 6th group of the periodic table, so it has 7 valence electrons. - There is one negative charge, which contributes an additional electron. - Therefore, the total number of valence electrons is: 7(I) + 7(F) + 1(-) = 15 electrons.
Step 2**Step 2:** Draw the Lewis structure for the IF$^-$ ion.
- Place I as the central atom, surrounded by F atoms. - Distribute the 15 valence electrons around the I and F atoms using single bonds (2 electrons) and lone pairs (2 electrons). - The structure should have a single bond between I and each F atom, with one lone pair on I and three lone pairs on each F atom.
Final Answer
** The molecular geometry of IF$^-$ is trigonal bipyramidal, and the shape is a distorted seesaw.
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