QQuestionAnatomy and Physiology
QuestionAnatomy and Physiology
Write a Lewis structure for methyl bromide, $\mathrm{CH}_{3} \mathrm{Br}$, showing all valence electrons.
- You do not have to consider stereochemistry.
- Explicitly draw all H atoms.
- Include all valence lone pairs in your answer.
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Answer
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Step 1: Determine the total number of valence electrons in the molecule.
Total valence electrons in $\mathrm{CH}_{3} \mathrm{Br} = 4 \text { (from C) }+3(1 \text { (from H) })+7 \text { (from Br) }=15$ valence electrons
Carbon is in the 4th group, hydrogen is in the 1st group, and bromine is in the 7th group. Thus, carbon has 4 valence electrons, hydrogen has 1 valence electron, and bromine has 7 valence electrons.
Step 2: Draw the skeletal structure of the molecule.
Place the central atom, carbon, in the center and connect it to the other atoms with single bonds. In this case, there will be one bromine atom and three hydrogen atoms bonded to the carbon atom.
Final Answer
The Lewis structure for methyl bromide, $\mathrm{CH}_{3} \mathrm{Br}$, is shown above, with all valence electrons explicitly displayed.
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