Q
QuestionChemistry

Write Lewis structures that obey the octet rule for the following species. Assign the formal charge for each central atom. XeO^4 ​
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Answer

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Step 1
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Step 2
: Determine the total number of valence electrons

• Total valence electrons: $$8 + 24 = 32$$ electrons
• Xe (Xenon): 8 valence electrons • O (Oxygen): 6 × 4 = 24 valence electrons

Final Answer

Lewis structure for XeO^4 with formal charges of + 4 for Xe and 0 for each oxygen atom.