Solution Manual For Introduction To Engineering Experimentation, 3rd Edition

Name: Solution Manual For Introduction To Engineering Experimentation, 3rd Edition
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Author: Madison Taylor

Solution Manual For Introduction To Engineering Experimentation, 3rd Edition offers step-by-step solutions to help you understand tough concepts with ease.

Madison Taylor

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7 months ago

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1.1
CHAPTER 1
1.1 (a) The weight of a person is 175 pounds which is equivalent to 778 Newtons.lbf175
*lbf
N
1
4482.4 = 778 Newtons
(b) The magnetic force of 1,200 dynes is equivalent to 0.0027 pounds or 0.012 Newtons.dyn1200
*dyn
N
1
10 5− = 0.012 Newtonsdyn1200
*dyn
N
1
10 5− *N
lbf
4482.4
1 = 0.0027 pounds
(c) The force exerted by the spring is 10 Newtons which is equivalent to 1,000,000 dynes or
2.248 poundsN10
*N
dyn
5
10
1 − = 1,000,000 dyneN10
*N
lbf
4482.4
1 = 2.248 pounds
1.2 (a) The tire pressure is 30 psig which is equivalent to 2.069 bars or 2.041 atm.
Note: 1 psig is considered to be = 1 psipsig30
*psi
atm
696.14
1 = 2.041 atmpsig30
*psi
kPa
1
895.6 *kPa
bar
100
1 = 2.069 bars
(b) The compressed air at 10 bars is equivalent to 145 psig or 9.87 atm or 295.3 inches of
mercury or 102 meters of waterbars10
*bar
kPa
1
100 *kPa
psi
895.6
1 = 145 psibars10
*bar
kPa
1
100 *kPa
psi
895.6
1 *

1.2
1.3 (a) The household energy use of 750 kWh is equivalent to 2,559,241.71 Btu or 645,007
kCal or 2,700,000,000 jouleskWh750
*kWh
kJ
1
3600 *kJ
J
1
1000 *J
Btu
1055
1 = 2,559,241.71 BtukWh750
*kWh
kJ
1
3600 *kJ
J
1
1000 *J
cal
186.4
1 *cal
kcal
1000
1 = 645,007 kcalkWh750
*kWh
kJ
1
3600 *kJ
J
1
1000 = 2,700,000,000 J
(b) The gas water heater uses 50,000 Btu or 52,750,000 joules or 12,601.5 kcal or
38,908,386 ft.lbfBtu50000
*Btu
J
1
1055 = 52,750,000 joulesBtu50000
*Btu
J
1
1055 *J
cal
186.4
1 *cal
kcal
1000
1 = 12,601.5 kcalBtu50000
*Btu
lbfft
00128507.0
.1 = 38,908,386 ft.lbf
(c) The amount of heat required is 250 kCal which is equivalent to 992 Btu or 250,000 Cal
or 1,046,500 jouleskcal250
*kcal
cal
1
1000 *cal
J
1
186.4 *J
Btu
1055
1 = 992 Btukcal250
*kcal
cal
1
1000 = 250,000 calkcal250
*kcal
cal
1
1000 *cal
J
1
186.4 = 1,046,500 J

1.3
1.4 (a) The automobile rating of 150 hp is equivalent to 112 kW or 82,500 ft.lbf/sec or
106.02 Btu/sechp150
*hp
W
1
7.745 *W
kW
1000
1 = 112 kWhp150
*hp
s
lbfft
1
.
550 = 82,500 ft.lbf/sechp150
*hp
W
1
7.745 *W
s
Btu
04.1055
1 = 106.02 Btu/sec
(b) The truck rating of 400 kW is equivalent to 536 hp or 295,025 ft.lbf/sec or 379 Btu/seckW400
*kW
W
1
1000 *W
hp
7.745
1 = 536 hpkW400
*kW
W
1
1000 *W
hp
7.745
1 *hp
s
lbfft
1
.
550 = 295,025 ft.lbf/seckW400
*kW
W
1
1000 *W
s
Btu
04.1055
1 = 379 Btu/sec
(c) The water heater rating of 40,000 Btu/hr is equivalent to 11.72 kWhr
Btu
40000
*hr
Btu
W
1
293.0 *W
kW
1000
1 = 11.72 kW

1.4
1.5 (a) 50 oF is equivalent to 10 oC
(9
5 )(50 – 32) = 10 oC
(b) 150 oC is equivalent to 302 oF
(5
9 )(150 oC) + 32 = 302 oF
(c) The water temperature increase of 40 oC is equivalent to a change of 40 K or 72 oF or 72
oR
(40 oC) *C
K


1
1 = 40 K
(40 oC) *C
F


1
8.1 = 72 oF
(40 oC) *C
R


1
8.1 = 72 oR
(d) The air temperature change of 30 oF is equivalent to a change of 16.7 K or 16.7 oC or 30
oR
(30 oF) *F
K


1
556.0 = 16.7 K
(30 oF) *F
C


1
556.0 = 16.7 oC
(30 oF) *F
R


1
1 = 30 oR

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Solution Manual For Introduction To Engineering Experimentation, 3rd Edition

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