Fundamental concepts and methods in statistical analysis
Lily Green
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Page1of14Stat200Introduction to StatisticsName______________________________Answer SheetRecord your answers andwork.ProblemNumberSolution1(25 pts)Answers:(a)True(b)True(c)False(d)True(e)FalseWork for (a), (b), (c), (d) and (e):2(5 pts)Answer:70%Work:CheckoutTimeFrequency(in minutes)1.0-1.922.0-2.9123.0-3.924.0-4.94Total20percentage of the checkout times was less than 3 minutes = 14/20 = 0.7= 70%3(5 pts)Answer:2ndclass:2.0-2.9Work:Here, n = 20,Median = n/2th observation when n = even,Here, n = 20/2th obs = 10thobservation. Thus median is expected to lie in 2ndclasswhich is 2.0–2.9.
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