Back to AI Flashcard MakerStatistics /Unit 5 Data Lesson 3 - Geometric Distributions
Unit 5 Data Lesson 3 - Geometric Distributions
This deck covers key concepts of geometric distributions, including conditions, probability calculations, and expected value.
new condition for geometric distribution
New condition for geometric distribution - determining how many trials will occur before our first success occurs.
Tap or swipe ↕ to flip
Swipe ←→Navigate
1/3
Key Terms
Term
Definition
new condition for geometric distribution
New condition for geometric distribution - determining how many trials will occur before our first success occurs.
how to do geometric probability
Example: Determine the probability of producing 3 cars before finding a defect if the probability of a defect is 1%.
The formula for geometric distri...
expected value
Expected value
E(x) = q/p
Related Flashcard Decks
Study Tips
- Press F to enter focus mode for distraction-free studying
- Review cards regularly to improve retention
- Try to recall the answer before flipping the card
- Share this deck with friends to study together
| Term | Definition |
|---|---|
new condition for geometric distribution | New condition for geometric distribution - determining how many trials will occur before our first success occurs. |
how to do geometric probability | Example: Determine the probability of producing 3 cars before finding a defect if the probability of a defect is 1%.
The formula for geometric distribution probability is:
P(x) = (q^x) (p) where x is the number of failures before the first success, p is the probability of success and q is the probability of failure
P(x) = (q^x) (p)
= 0.99^3 (0.01)
=0.0097
The probability is 0.0097 or 0.97% chance of finding a defect |
expected value | Expected value
E(x) = q/p |