QQuestionBiology
QuestionBiology
For each atom in the table below, write down the subshell from which an electron would have to be removed to make a + 1 cation and the subshell to which an electron would have to be added to make a - 1 anion. The first row has been completed for you.
| Atom | Subshell from which electron
removed to form + 1 cation | Subshell to which electron
added to form - 1 anion |
| --- | --- | --- |
| H | 1s | 1s |
| Hg | | |
| Ne | | |
| K | | |
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Step 1: Determine the subshell from which an electron should be removed to form a + 1 cation for Hg.
Hg has the electron configuration of [Xe] 4f^{14} 5d^{10} 6s^{2}. To form a + 1 cation, we need to remove one electron. The outermost shell is the 6s subshell, which contains two electrons. Removing one electron will leave one electron in the 6s subshell. However, we want to form a + 1 cation, so we need to remove one more electron, which will be from the 5d subshell as it is the next subshell with electrons. Subshell from which electron removed to form + 1 cation for Hg: 5d
Step 2: Determine the subshell to which an electron should be added to form a - 1 anion for Hg.
To form a - 1 anion, we need to add one electron to a neutral Hg atom. Since Hg has a closed shell configuration of [Xe] 4f^{14} 5d^{10}, the added electron should go to the next available subshell, which is the 6s subshell. Subshell to which electron added to form - 1 anion for Hg: 6s
Final Answer
| Atom | Subshell from which electron removed to form + 1 cation | Subshell to which electron added to form - 1 anion | | --- | --- | --- | | H | 1s | 1s | | Hg | 5d | 6s | | Ne | 2s | 3s | | K | 4s | 4p |
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