CHEM103 Final Exam With Answers (12 Solved Questions)
CHEM103 Final Exam With Answers ensures you cover all important topics with real past questions.
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Question 1
Complete the two problems below:
1. Convert 0.0000726 to exponential form and explain your answer.
2. Convert 5.82 x 103 to ordinary form and explain your answer.
Answer:
1.Convert 0.0000726 = smaller than 1 = negative exponent, move decimal 5
places = 7.26 x 10-5
2.Convert 5.82 x 103 = positive exponent = larger than 1, move decimal 3
places = 5820
Question 2
Do the conversions shown below, showing all work:
1. 358oK = ? oC
2. 53oC = ? oF
3. 158oF = ? oK
Answer:
1. 358oK - 273 = 85 oC oK → oC (make smaller)
-273
2. 53oC x 1.8 + 32 = 127.4 oF oC → oF (make larger) x
1.8 + 32
3. 158oF - 32 ÷ 1.8 = 70 + 273 = 343 oK oF → oC → oK
Question 3
Show the calculation of the number of moles in the given amount of the
following substances. Report your answerto 3 significant figures.
1. 12.0 grams of Ca3(PO4)2
Question 1
Complete the two problems below:
1. Convert 0.0000726 to exponential form and explain your answer.
2. Convert 5.82 x 103 to ordinary form and explain your answer.
Answer:
1.Convert 0.0000726 = smaller than 1 = negative exponent, move decimal 5
places = 7.26 x 10-5
2.Convert 5.82 x 103 = positive exponent = larger than 1, move decimal 3
places = 5820
Question 2
Do the conversions shown below, showing all work:
1. 358oK = ? oC
2. 53oC = ? oF
3. 158oF = ? oK
Answer:
1. 358oK - 273 = 85 oC oK → oC (make smaller)
-273
2. 53oC x 1.8 + 32 = 127.4 oF oC → oF (make larger) x
1.8 + 32
3. 158oF - 32 ÷ 1.8 = 70 + 273 = 343 oK oF → oC → oK
Question 3
Show the calculation of the number of moles in the given amount of the
following substances. Report your answerto 3 significant figures.
1. 12.0 grams of Ca3(PO4)2
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Document Details
University
Portage Learning
Subject
Chemistry