Solution Manual For Fundamentals of Heat and Mass Transfer, 8th Edition

Solution Manual For Fundamentals of Heat and Mass Transfer, 8th Edition is your textbook problem-solver, offering clear and concise solutions to difficult questions.

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PROBLEM 1.1KNOWN:Temperature distribution in wall of Example 1.1.FIND:Heat fluxes and heat rates atx= 0 andx = L.SCHEMATIC:ASSUMPTIONS:(1) One-dimensional conduction through the wall, (2) constant thermal conductivity,(3) no internal thermal energy generation within the wall.PROPERTIES:Thermal conductivity of wall (given):k= 1.7 W/m·K.ANALYSIS:The heat flux in the wall is by conduction and is described by Fourier’s law,xdTqk dx′′ = −(1)Since the temperature distribution isT(x) =a+bx, the temperature gradient isdTbdx=(2)Hence, the heat flux is constant throughout the wall, and is()21.7 W/m K1000 K/m1700 W/mxdTqkkbdx′′ = −= −= −× −=<Since the cross-sectional area through which heat is conducted is constant, the heat rate is constant and is()2()1700 W/m1.2 m × 0.5 m1020 WxxqqWH′′=××=×=<Because the heat rate into the wall is equal to the heat rate out of the wall, steady-state conditions exist.<COMMENTS:(1)If the heat rates were not equal, the internal energy of the wall would be changingwith time. (2) The temperatures of the wall surfaces areT1= 1400 K andT2= 1250 K.

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