Solution Manual for Fundamentals of Heat and Mass Transfer, 7th Edition

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PROBLEM 1.1KNOWN:Thermal conductivity, thickness and temperature difference across a sheet of rigidextruded insulation.FIND:(a) The heat flux through a 2 m×2 m sheet of the insulation, and (b) The heat ratethrough the sheet.SCHEMATIC:ASSUMPTIONS:(1) One-dimensional conduction in the x-direction, (2) Steady-stateconditions, (3) Constant properties.ANALYSIS:From Equation 1.2 the heat flux is12xT - TdTq= -k= kdxL′′Solving,"xW10 Kq= 0.029×m K0.02 mx2Wq= 14.5 m′′<The heat rate is2xx2Wq= qA = 14.5× 4 m= 58 Wm′′ ⋅<COMMENTS:(1)Be sure to keep in mind the important distinction between the heat flux(W/m2) and the heat rate (W). (2) The direction of heat flow is from hot to cold. (3) Note thata temperaturedifferencemay be expressed in kelvins or degrees Celsius.qcondA = 4 m2T2T1k = 0.029Wm KxL = 20 mmT1– T2= 10˚CqcondA = 4 m2T2T1k = 0.029Wm KxL = 20 mmT1– T2= 10˚C

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