OCR A-Level Chemistry: Module 6 - Organic Chemistry & Analysis
This flashcard set focuses on reactions involving aromatic compounds, including the reduction of nitro groups, basic understanding of functional groups like amines, and the role of reagents such as [H], NaOH, and tin/HCl in organic transformations.
What does the symbol [H] represent? (1)
Reducing agent
Key Terms
What does the symbol [H] represent? (1)
Reducing agent
Suggest a reagent that would convert the -OH group in phenol to an -O(-) group (1)
NaOH
1,4-dinitrobenzene is converted to 1,4-diaminobenzene, what type of reaction is this? (1)
Reduction
State reagents and conditions required to convert 1,4-dinitrobenzene to 1,4-diaminobenzene (2)
Tin and HCl
Conc acid under reflux
Explain how the amino groups in a primary amine allow the molecule to act as a base (2)
Accepts H+ using the lone pair on N
Which forms a dative covalent bond
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| Term | Definition |
|---|---|
What does the symbol [H] represent? (1) | Reducing agent |
Suggest a reagent that would convert the -OH group in phenol to an -O(-) group (1) | NaOH |
1,4-dinitrobenzene is converted to 1,4-diaminobenzene, what type of reaction is this? (1) | Reduction |
State reagents and conditions required to convert 1,4-dinitrobenzene to 1,4-diaminobenzene (2) | Tin and HCl Conc acid under reflux |
Explain how the amino groups in a primary amine allow the molecule to act as a base (2) | Accepts H+ using the lone pair on N Which forms a dative covalent bond |
State whether you would expect hexane-1,6-diamine to be a stronger or weaker base than 1,4-diaminobenzene. Explain your reasoning (3) | Hexane-1,6-diamine is a stronger base because: |
Suggest possible problems of making a chiral drug such as salbutamol and describe two | Production of a single isomer is more expensive One of the isomers is more active Overcome by using: Enzyme catalyst Chiral catalyst |
Explain what is meant by an α-amino acid (1) | Both NH2 and COOH are joined to the same C |
Explain the evidence that led scientists to doubt the model proposed by Kekulé (3) | Bond length intermediate between/different from (short) C=C and (long) C–C |
The chemist observed that bromine decolourises when it reacts with phenol | White precipitate |
Cyclohexene also decolourises bromine Name the organic product formed (1) | 1,2-Dibromocyclohexane |
Explain the relative resistance to bromination of benzene compared to phenol and compared to cyclohexene (5) | Benzene - π bonds are delocalised Phenol - a lone pair of electrons on the OH is partially delocalised into the ring Cyclohexene - electrons are localised Benzene has a lower electron density Benzene cannot induce a dipole in Br2 |
State the general formula of an α-amino acid (1) | C bonded to NH2, COOH, H and R |
The mixture of tripeptides can be analysed by using gas chromatography, coupled with mass spectrometry. Summarise how each method contributes to the analysis (3) | Gas chromatograph separates the tripeptides |
State what is meant by the term zwitterion (1) | Ion has both + and - charges |
What is meant by the term stereoisomer? (1) | Molecules with the same structure but different arrangements in space |
How does cis-trans isomerism arise in organic molecules? (1 | Double bond does not rotate |
State a use for Kevlar (1) | Bullet proof clothing |
Kevlar is formed from a diamine and a dioic acid, what kind of polymerisation is this reaction? (1) | Condensation` |
Chlorobenzene can be nitrated to form a mixture of products. Suggest why the reaction forms a mixture of products (1) | Nitration at different positions on the ring |
State what the biochemist would see when hydroxyethanal reacts with | Silver mirror |
The biochemist also reacted hydroxyethanal with acidified dichromate by heating | HOCH2CHO + 3[O] -> HOOCCOOH + H2O |
The biochemist then reduced hydroxyethanal using aqueous NaBH4. | HOCH2CH2OH |
What is meant by the term nucleophile? (1) | Electron pair donor |
Describe a simple chemical test that would show that but-2-enal is an aldehyde (2) | Heat with Tollens' reagent | Gives a silver mirror |
Explain why Tollens' reagent test gives a different result for aldehydes and ketones (1) | Aldehydes can reduce Ag+ to Ag |
Tollens’ reagent can be used to identify the aldehyde group in cinnamaldehyde. (6) | Method: Silver nitrate Ammonia Heat Silver mirror forms Explanation: Silver ions reduced Aldehyde oxidised to a carboxylic acid |
How does gas chromatography separate the compounds in the mixture? (1) | Relative solubility in stationary phase |
Two compounds pass through a gas chromatogram, what is suggested about the one that comes out first? (1) | Less soluble in the stationary phase |
Three compounds: Ketone & primary alcohol (A), Aldehyde & secondary alcohol (B), Ketone & tertiary alcohol (C) Describe chemical tests to distinguish between the compounds (4) | First react all with Tollens' reagent, silver mirror forms with compound B |
An alcohol is reacted with excess K2Cr2O7/H2SO4 under reflux, state observation during reaction? (1) | Colour changes from orange to green |
Describe a chemical test that you could use to detect the presence of a carbonyl group in an organic compound, reagent and observation (2) | 2,4-DNPH | Orange precipitate |
State one possible health risk of a diet that is high in trans oils (1) | Heart disease |
A chemical with chiral centres can be synthesised from naturally occuring steroids. Suggest an advantage of having a synthetic route (1) | Ensures correct chirality |
Explain what is meant by the term condensation polymerisation (1) | Monomers form polymer and a small molecule i.e H2O |
Before any skin cream can be sold to the public, it must be tested to ensure it is safe to | To test for adverse side effects |
Methylglyoxal, CH3COCHO, is formed in the body during metabolism. | Methylglyoxal is reduced by NaBH4 |
A synthetic polymer can be easily hydrolysed compared with other synthetic polymers, explain why it is thought polymers such as this one are better for the environment (1) | Biodegradable, whereas hydrocarbon based polymers are not |
| Peak in range 2500-3300 |
The aldehyde has the molecular formula C5H10O. | Relative peak area indicates 2 x CH3 in the same environment | (CH3)2CH-CH2-CHO |
State what is meant by retention time (1) | The time from the injection of the sample for the component to leave the column |
How could a specific carbonyl be identified not using spectroscopy after reaction with 2,4-DNPH? (2) | Take melting point of orange crystals | Compare melting point with known values |
Outline purification (4) | Recrystallisation |
Phenol undergoes easier nitration than benzoic acid, explain this (3) | Lone pair of OH partially delocalises into ring |
Suggest why a polyester is biodegradable (1) | Ester bond can be hydrolysed |
A CHO based molecule is slightly acidic but has no visible change when Na2CO3 is added, suggest the functional group responsible (1) | Phenol |
Explain why phenol is nitrates more readily than benzene (3) | In phenol a lone pair of electrons on O is donated into π system |
Explain what is meant by molecular ion peak (1) | Peak caused by unfragmented molecule |
Explain what is meant by base peak (1) | Peak with the greatest relative intensity |
Name the process by which TLC separates α-amino acids (1) | Adsorption |
A student used TLC to separate three different α-amino acids, explain how the student could analyse the chromatogram to identify the α-amino acids present (2) | Calculate the Rf value | Compare Rf values to those known for amino acids |
Several α-amino acids have structures that are very similar. Suggest why this could cause problems when using TLC to analyse mixtures of α-amino acids (1) | Amino acids won't separate because similar compounds have similar Rf values |
Define Rf value (1) | Distance moved by a component divided by distance moved by solvent |
What are the roles of the gas and liquid in gas/liquid chromatography? (2) | Role of gas: Mobile phase | Role of liquid: Stationary phase |
Explain how the gas/liquid chromatogram could be used to determine the percentage composition of each component in the mixture (3) | Measure area under each peak |