MM207 Unit 5: Normal Distribution, Probabilities, and Sampling Distributions

Examines normal distribution and sampling techniques.

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MM207 Unit 5 Chapter 5 ProjectROBYN GALINDO1MM207 Unit 5: Normal Distribution, Probabilities, and SamplingDistributionsTotal points are 40. Points are included with each problem.Includedwith each section or problem arereference examples and end of sectionexercises that can be used as a guide.Be sure to show your work incase partialcredit is awarded.To receive full credit, work must be shown if applicable.Section5.1: Introduction to Normal Distribution and the Standard NormalDistribution1.Use the Standard Normal Distribution table to find the indicated area under thestandard normal curve.(References: example 3-6pages 244-247, end of section exercises21–40page 249)(2pointsper each part)a.Between z = 0 and z = 1.42The area to the left of z = 0 is 0.5000.The area to the left of z = 1.42 is 0.9222.The area between z = 0 and z = 1.42 is 0.4222.b.To the left of z = 1.86The area to the left of z = 1.86 is 0.9686.c.Between z =-1.52 and z =-0.46The area to the left of z =-1.52 is 0.0643.The area to the left of z =-0.46 is 0.3228.The area between z =-1.52 and z =-0.46 is0.2585.d.To the right of z =-1.45The area to the right of z =-1.45 is 1-.0735 =0.9265.Section 5.2: Normal Distributions: Find Probabilities(References: example 1 and 2page 253, end of section exercises 13-30pages 257-2592.The diameters of a wooden dowel produced by a new machine arenormally distributed with a mean of 0.55 inches and a standard deviation of0.01 inches.What percent of the dowels will have a diameterlessthan 0.56?(6points)Z = (0.56–0.55) / .01 = 1 = 0.841384.13% of the dowels will have a diameter of less than 0.56.

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