MM207 Unit 6: Confidence Intervals for Means and Population Proportions
Discusses confidence intervals and their application in statistics.
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MM207 Unit 6 Chapter 6 ProjectROBYN GALINDO1MM207 Unit 6: Confidence Intervals for Means and PopulationProportionsTotal points are40. Points are included with each problem.Included with each section or problem are reference examples and end of sectionexercises that can be used as a guide.Be sure to show your work incase partialcredit is awarded.To receive full credit, work must be shown if applicable.Section 6.1: Confidence Intervals for the Mean (Large Samples)1.Find the critical value zcnecessary to form a confidence interval at the givenlevel of confidence.(References: definition for level of confidencepage311, end of section exercises5–8 page 317)(2.5points each)a.90%½ (1-.90) =0.05 = 1.645b.80%½ (1-.80) = 0.10= 1.282.The new Twinkle bulb has a standard deviation35hours. A randomsample of 50light bulbs is selected from inventory.Thesamplemeanwasfound to beX550hours.a.Find the margin of error Efor a 90% confidence interval.(5 points)Round your answer to the nearest hundredths..(References:definition of margin of error on page 312 and example 2 onpage 312).E = 1.645 (35/√50) = 8.14b.Construct a 90% confidence interval for the mean life,of all Twinklebulbs.(5 points)(References: example 5page 315, end ofsection exercises51-56pages 319-320)Left Endpoint:550–8.14 = 541.86Right Endpoint:550 + 8.14 = 558.14541.86 <μ< 558.143. A standard placement test has a mean of 115and a standard deviation of= 10. Determine the minimumsample size if we want to be 90% certainthat we arewithin 2pointsof the true mean.(References: example 6page 316, end of section exercises58-62pages 321-322)(5points)n = (1.645)(10)² = 271Section 6.2: Confidence Intervals for the Mean (Small Samples)