Reliability Analysis and Maintenance Strategies for Complex Systems and Components
Evaluation of reliability and maintenance strategies for complex systems.
Emma Thompson
Contributor
4.4
47
4 days ago
Preview (2 of 5)
Sign in to access the full document!
Reliability Analysis and Maintenance Strategies for
Complex Systems and Components
A power supply consists of three rectifires in series. Each rectifier has a Weibull
failure didtribution with eqaul to 2.1. However they have different
characteristics lifetimes given by 12,000 hr, 18,500 hr and 21,500 hr. Find the
MTTF and the design life of the power supply corresponding to a reliability of
0.90.
Given values:
failure didtribution with eqaul to 2.1. with different life times as
1 2 3 2.1
31 2
2.1 2.1 2.1
2.1
1 2 3
1 2 3
// /
1 2 3
/12,000 /18,500 / 21,500
1 1
12000 185
2.1
12, 000 ; 18,500 ; 21,500
for weibul distribution,
R t t Qt Q t Q
t t t
t
Q hrs Q hrs Q hrs
R R R e e e
e e e
e
2.1
2.1 9
2.1 9
1
00 21500
1 1 1
12000 18500 21500
0
4.6 10
0
4.6 10
2.1 9
,
Design T for R t 0.9
0.9
ln 0.9 4.6 10
3196.16
3197 .
t
t
t
Now MTTF e dt
e dt
e
t
t
t hrs
A system has two failure modes. One failure mode due to external conditions,
has a constant failure rate of 0.07 failure per year. The second attributed to
wearout, has a Weibull distribution with a characteristics life of 10 year and a
shape parameter of 1.8. Determine the system reliability for a design life of 1
year. Find by trial and error the median time of failure
Complex Systems and Components
A power supply consists of three rectifires in series. Each rectifier has a Weibull
failure didtribution with eqaul to 2.1. However they have different
characteristics lifetimes given by 12,000 hr, 18,500 hr and 21,500 hr. Find the
MTTF and the design life of the power supply corresponding to a reliability of
0.90.
Given values:
failure didtribution with eqaul to 2.1. with different life times as
1 2 3 2.1
31 2
2.1 2.1 2.1
2.1
1 2 3
1 2 3
// /
1 2 3
/12,000 /18,500 / 21,500
1 1
12000 185
2.1
12, 000 ; 18,500 ; 21,500
for weibul distribution,
R t t Qt Q t Q
t t t
t
Q hrs Q hrs Q hrs
R R R e e e
e e e
e
2.1
2.1 9
2.1 9
1
00 21500
1 1 1
12000 18500 21500
0
4.6 10
0
4.6 10
2.1 9
,
Design T for R t 0.9
0.9
ln 0.9 4.6 10
3196.16
3197 .
t
t
t
Now MTTF e dt
e dt
e
t
t
t hrs
A system has two failure modes. One failure mode due to external conditions,
has a constant failure rate of 0.07 failure per year. The second attributed to
wearout, has a Weibull distribution with a characteristics life of 10 year and a
shape parameter of 1.8. Determine the system reliability for a design life of 1
year. Find by trial and error the median time of failure
Preview Mode
Sign in to access the full document!
100%
Study Now!
XY-Copilot AI
Unlimited Access
Secure Payment
Instant Access
24/7 Support
Document Chat
Document Details
Subject
Engineering