SCI103 Phase 5 Lab Report: Exploring Potential and Kinetic Energy
A lab report in Physics 103, exploring potential and kinetic energy concepts.
David Miller
Contributor
4.3
50
about 1 month ago
Preview (2 of 3)
Sign in to access the full document!
SCI103 Phase 5 Lab Report: Exploring Potential and Kinetic Energy
Name: Michelle Kleszynski
Date: 2/3/13
Instructor’s Name: Nemmers
Assignment: SCI103 Phase 5 Lab Report
TITLE: Potential and Kinetic Energy
INSTRUCTIONS: Enter the Virtual Lab and conduct the experiments provided. Please
type your answers. When your lab report is complete, submit it to the Submitted
Assignments area of the Virtual Classroom.
Part I – Answer the following questions while in the Phase 5 lab environment.
Section 1 – From the left of the screen to the right, the red balls have a center of mass placed at
20 feet, 15 feet, and 10 feet high respectively.
1. Suppose each red ball weighs 20 lbs. Find the potential energy (PE) for each ball
on each ramp.
PE=mgh + 20lbs x 32.17 x 20 ft PE=12868 foot-Pounds
PE=mgh 20 lbs x 32.17 x 15 ft PE= 9651 foot-pounds
PE= mgh 20 lbs x 32.17 x 10 ft PE= 6434 foot pounds
2. Predict the maximum speed of the ball on each ramp. How would this speed
change if each ball’s mass was doubled? KE=1/2mv2
KE= ½ 20lbs x 12868 squared= ½ would be 10/12868= 1286.8 squared
=KE=35.87 m/sec
KE=1/2 20lbs x 9651 squared= ½ would be 10/9651=965.1 squared
=KE=31.07m/sec
KE= ½ 20lbs x 6434 squared= ½ would be 10/6434= 634.3 squared
KE= 25.37 m/sec
If the mass what doubled the KE would = 20/12868 KE=25.37 m/sec
20/9651 KE= 22 m/sec
20/6434 KE= 17.93 m/sec
The speed would go down when you add more weight.
3. On ramp 1, calculate the balls potential and kinetic energy at 16 feet.
PE=mgh 20lbs x 32.17 x 16ft PE= 10294.4 foot-pounds
KE= ½ 20lbs x 10294.4 squared+ ½ would be 10/10294.4 =1029.44 squared
KE=32.08 m/sec
Name: Michelle Kleszynski
Date: 2/3/13
Instructor’s Name: Nemmers
Assignment: SCI103 Phase 5 Lab Report
TITLE: Potential and Kinetic Energy
INSTRUCTIONS: Enter the Virtual Lab and conduct the experiments provided. Please
type your answers. When your lab report is complete, submit it to the Submitted
Assignments area of the Virtual Classroom.
Part I – Answer the following questions while in the Phase 5 lab environment.
Section 1 – From the left of the screen to the right, the red balls have a center of mass placed at
20 feet, 15 feet, and 10 feet high respectively.
1. Suppose each red ball weighs 20 lbs. Find the potential energy (PE) for each ball
on each ramp.
PE=mgh + 20lbs x 32.17 x 20 ft PE=12868 foot-Pounds
PE=mgh 20 lbs x 32.17 x 15 ft PE= 9651 foot-pounds
PE= mgh 20 lbs x 32.17 x 10 ft PE= 6434 foot pounds
2. Predict the maximum speed of the ball on each ramp. How would this speed
change if each ball’s mass was doubled? KE=1/2mv2
KE= ½ 20lbs x 12868 squared= ½ would be 10/12868= 1286.8 squared
=KE=35.87 m/sec
KE=1/2 20lbs x 9651 squared= ½ would be 10/9651=965.1 squared
=KE=31.07m/sec
KE= ½ 20lbs x 6434 squared= ½ would be 10/6434= 634.3 squared
KE= 25.37 m/sec
If the mass what doubled the KE would = 20/12868 KE=25.37 m/sec
20/9651 KE= 22 m/sec
20/6434 KE= 17.93 m/sec
The speed would go down when you add more weight.
3. On ramp 1, calculate the balls potential and kinetic energy at 16 feet.
PE=mgh 20lbs x 32.17 x 16ft PE= 10294.4 foot-pounds
KE= ½ 20lbs x 10294.4 squared+ ½ would be 10/10294.4 =1029.44 squared
KE=32.08 m/sec
Preview Mode
Sign in to access the full document!
100%
Study Now!
XY-Copilot AI
Unlimited Access
Secure Payment
Instant Access
24/7 Support
Document Chat
Document Details
University
Colorado Technical University
Subject
Physics