Solution Manual for Transport Processes and Separation Process Principles, 5th Edition
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Solution Manual for Transport Processes and Separation Process Principles Fifth Edition Christie John Geankoplis A. Allen Hersel Daniel Lepek Ancillary material to Geankoplis, et al., Transport Processes and Separation Process Principles, 5/E, ISBN: 9780134181028. Page 2
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(1.2-1) Eq. (1.3-4) k 353.2 °C 273.15 °C 80.05 80 C = = + = = ° Eq. (1.3-2) °C 80.0 1/1.8 F 32 F 176°F = = ° ° = Eq. (1.3-3) °R °F 460 176 460 °R 636°R = + = + = Ancillary material to Geankoplis, et al., Transport Processes and Separation Process Principles, 5/E, ISBN: 9780134181028. Page 4
(1.2-2) Eq. (1.3-2) °C 1 1.8 °F 32 1/1.8 155 32 68.33°C = = = Eq. (1.3-4) K °C 273.15 68.33 273.15 341.5K = + = + = Eq. (1.3-3) °R °F 460 155 460 615°R = + = + = Ancillary material to Geankoplis, et al., Transport Processes and Separation Process Principles, 5/E, ISBN: 9780134181028. Page 5
(1.3-1) 2 2 MW O 32.00, MW N 28.02 MW air 0.21 32.00 0.79 28.02 28.9 kg / kg mol Ancillary material to Geankoplis, et al., Transport Processes and Separation Process Principles, 5/E, ISBN: 9780134181028. Page 6
(1.3-2) 2 2 MW 28.01 32.00 44.01 56.0 kg 2CO O 2CO moles CO 2.00 kg mol 28.01kg/kg mol + = = 2 2 2 moles O 1.00, 1.00 32.00 32.0kg O 2.00 44.0 88.0Kg CO Ancillary material to Geankoplis, et al., Transport Processes and Separation Process Principles, 5/E, ISBN: 9780134181028. Page 7
(1.3-3) Gas g MW g mol mol/sec N 2 20 28.02 0.7138 0.1648 mol/sec O 2 83 32.00 2.5938 0.5990 CO 2 45 44.01 1.0225 0.2362 Total 148 g 4.330/g mol 1.0000 34.2g/g mol 148g Average mol wt 34.2 kg/kg mol 4.3301g mol = = Ancillary material to Geankoplis, et al., Transport Processes and Separation Process Principles, 5/E, ISBN: 9780134181028. Page 8
(1.3-4) Ancillary material to Geankoplis, et al., Transport Processes and Separation Process Principles, 5/E, ISBN: 9780134181028. Page 9
(1.3-5) Ancillary material to Geankoplis, et al., Transport Processes and Separation Process Principles, 5/E, ISBN: 9780134181028. Page 10
(1.4-1) P = 2.4 mm Hg From Appendix A.1 1 atm = 760 mm Hg 3 2.4 mm Hg P 3.16 10 atm 760 mm Hg/atm 1 atm = 33.90 × 12 in. H 2 O (at 4°C) 2 2 in.H O 2.4 P atm 33.90 12 1.285in.H O 760 atm 1 μm = 10 −3 mm 3 2.4 mm P 2, 400 μm Hg 10 mm/ μm