Solution Manual for Microbiology with Diseases by Body System, 4th Edition

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207
Answers to End-of-Chapter
Questions for Review
Note that the End-of-Chapter Concept Maps are available online in the Study Area of
Mastering Microbiology (www.masteringmicrobiology.com) so that students can complete
them interactively. Concept mapping answers are also found in the Answers section in the
back of the textbook. Instructors can access completed concept maps and teaching tips in the
Resource section of Mastering Microbiology.
CHAPTER 1 A Brief History of Microbiology
Multiple Choice
1. a 3. d 5. c 7. a 9. d
2. c 4. a 6. d 8. b 10. d
Fill in the Blanks
1. Martinus Beijerinck and Sergei Winogradsky
2. Louis Pasteur and Eduard Buchner
3. Paul Ehrlich
4. Edward Jenner
5. John Snow
6. Robert Koch
7. John Snow
8. Louis Pasteur
9. Louis Pasteur
Visualize It!
1. 1. cilium; 2. flagellum; 3. pseudopod; 4. nucleus
2. Microbes were only in the dust in the lowest portion of the swan neck tube.
Matching
1. J 4. C, H, K 7. C 10. D
2. H 5. B 8. E 11. I
3. C 6. A 9. D 12. L

208 MANUAL/TEST BANK FOR MICROBIOLOGY WITH DISEASES BY BODY SYSTEM, 4e
Short Answer
1. The theory of spontaneous generation hindered the development of the field of microbi-
ology because the theory seemed to explain observed phenomena such as food spoilage,
so further investigations were not made. Leeuwenhoek’s microscopic observations
revealed previously unseen microorganisms and advanced interest in microbiology.
2. Spallanzani’s flasks contained sterilized nutrients but were sealed from air, whereas
Pasteur’s flasks had sterilized nutrients in flasks with curves (“swan-necked” flasks),
which allowed air to enter but trapped microorganisms that fell in the tube. Although
Pasteur’s controlled investigation provided all the environmental and nutritional require-
ments for life to arise spontaneously, the flasks remained sterile. This settled the dispute.
3. Six types of microorganisms: archaea, bacteria, protozoa, fungi, algae, and worms.
4. Leeuwenhoek’s investigations changed the world by revealing the presence of microor-
ganisms. Subsequent investigations were directed at microorganisms, their taxonomy,
their effect on disease, disease control, and so on; and the result not only is of academic
interest but also affects the quality and duration of human life.
5. Macroscopic tapeworms are studied in microbiology because their eggs and infective
stages are microscopic and because of historical tradition.
6. “The Golden Age of Microbiology” was a 50-year period during which scientists
searched for the answers to four questions: (1) Is spontaneous generation of microbial life
possible? (2) What causes fermentation? (3) What causes disease? (4) How can we
prevent infections and disease? Applying the scientific method to their investigations,
biologists pioneered discoveries in disciplines such as industrial microbiology, genetics,
environmental microbiology, antiseptic medical technology, serology, immunology, and
chemotherapy. The season of discovery was “golden” to the field of microbiology.
7. Today, microbiological investigations are propelled by four major questions: (1) What
are the basic chemical reactions of life? (2) How do genes work? (3) What roles do mi-
croorganisms play in the environment? (4) How do we defend against disease?
8. Pasteur’s fermentation experiments followed the scientific method. (1) Pasteur observed
Needham’s investigations and questioned the source of microorganisms. (2) He hypothe-
sized that dust in the air contained microbes that would reproduce in nutrient broth. (3)
His experimental design (with controls) included heated infusion in “swan-necked
flasks,” which remained free of dust and therefore microbes unless the flasks were tilted
to allow the infusion to touch the dust in the curve of the flask. Those flasks that were
tilted showed microbial life. (4) Based on the results, Pasteur concluded that microbes in
the infusion were not spontaneous but rather were descendants of microbes in the air or
on dust particles.
9. Koch’s postulates are: (1) The suspected causative agent must be found in every case of
the disease and be absent from healthy hosts. (2) The agent must be isolated and grown
outside the host. (3) When the agent is introduced to a healthy, susceptible host, the host
must get the disease. (4) The same agent must be re-isolated from the diseased experi-
mental host. These postulates are significant because when they are satisfied, the cause of
an infectious disease is proven.
10. HAI is an acronym for healthcare-associated infections (formerly called nosocomial in-
fections). These terms refer to infections acquired in a healthcare setting. Their frequency
emphasizes the need for good hygiene in healthcare facilities.

Answers to End-of-Chapter Questions for Review 209
Critical Thinking
1. Koch would have been extremely frustrated by attempts to identify the agents of viral
diseases. Methods to detect viruses did not exist, and the means to grow viruses in the la-
boratory had not been developed. His initial success with anthrax provided the basis for
the development of his postulates, for the bacteriologic methodology his laboratory
devised, and for his renown. Had Koch pursued viral diseases, his lifetime accomplish-
ments would have been greatly reduced: fewer etiologic agents would have been identi-
fied, and doubt would have been cast on the power of his postulates.
2. Under the influence of Pasteur’s and Koch’s work, the Germ Theory of Disease had
become widely accepted in the early 1900s, and the prevailing belief in the scientific
community was that microorganisms caused all diseases. In this atmosphere, explana-
tions for disease that did not involve microbial infection were ridiculed. Biochemistry
was a very young science, and metabolism was just beginning to be investigated.
Although Funk’s interpretation of his observations was correct, he could not provide a
mechanism for how polished rice might promote disease.
3. Checking for the presence of H. influenzae in a large number of diagnosed cases of flu
would likely have cast doubt on the conclusion that H. influenzae was the cause of flu. In
some cases, H. influenzae is not present, and thus Koch’s first postulate would not be sat-
isfied. Further, inoculation of H. influenzae into an experimental organism would not
have produced flu, violating the third postulate.
4. The relatively low temperature used in pasteurization is not high enough, nor is heating
long enough in duration to destroy bacterial endospores or fungal spores. Any such
contaminants would have a chance to germinate and ferment the milk over winter break.
5. Pour the milk into sterile containers through a filter that will trap bacteria, endospores,
and spores, and then incubate in a sterile chamber or in a chamber with filtered vents that
allow air exchange but no microbial entry. If the sterile milk remains sterile, then sponta-
neous generation did not occur.
6. Identifying cholera cases in persons who visited the Broad Street area only during the
day would demonstrate that nocturnal exposure to “fermented vapors” was not the source
of cholera.
7. Redi showed that flies laid eggs that hatched onto larvae on meat by covering jars of
meat with gauze upon which the events took place. Needham’s experiments with boiled
infusions and gravy in sealed containers suggested that microbes arise spontaneously, but
Spallanzani repeated Needham’s experiments more rigorously and concluded that spon-
taneous generation of microorganisms does not occur. The absence of air exchange in
Spallanzani’s experiments caused some doubt about his conclusions. Pasteur demon-
strated the growth of microorganisms in supposedly sterile infusions in swan-necked
flasks, which remained sterile unless contaminated with nonsterile dust.
8. There are a number of possible answers, including infection control (hygiene and the
control of disease in health care settings); bioremediation (the use of microbes to remove
pollutants); pharmaceuticals (design and development of medications for infectious dis-
ease) and recombinant DNA technology (the alteration of microbial genes to synthesize
useful products).
9. Algae have simple nutritional requirements (carbon dioxide, water, light, a few salts) that
are easily obtained from the environment; therefore, they do not need to obtain nutrients
from other living things.

210 MANUAL/TEST BANK FOR MICROBIOLOGY WITH DISEASES BY BODY SYSTEM, 4e
10. Buchner’s experiments demonstrated that intact living cells were not required for fermen-
tation of sugars. Had the experiments been done in the 1850s, prior to Pasteur’s experi-
ments on spontaneous generation, one argument for spontaneous generation (the
appearance of yeast cells in fermenting sugar solutions) would have been weakened.
Spallanzani’s results might have been more widely accepted as demonstrating that spon-
taneous generation does not occur. When scientists accepted that animals do not arise
from spontaneous generation, they might have been less likely to exempt microorgan-
isms.
11. Many bacteria are very small and may be easily overlooked during examination with a
light microscope. In contrast, Koch’s method allows a single microbe to reproduce into a
much more visible population of cells—a colony—which is less likely to be overlooked.
In addition, many microorganisms, especially pathogens, have stringent nutritional re-
quirements; dilution in standard growth medium might be harmful to the microbes and
therefore prevent their detection.
12. Koch’s postulates are not useful in determining the cause of diseases that are not infec-
tions (e.g., Down syndrome, lung cancer). Some diseases (e.g., cholera) occur only under
specific conditions (high numbers, specific genetic component), so the microbes may be
present in asymptomatic persons, and Koch’s first postulate is not met. Disease caused by
microorganisms that are infectious only in humans is difficult to prove by Koch’s postu-
lates because ethical considerations prohibit deliberate exposure of humans to potential
harm (e.g., HIV/AIDS), preventing the third postulate from being applied. Some syn-
dromes are common to a variety of microbes (e.g., pneumonia), so identifying a single
causative agent is not possible (first postulate again). Alzheimer disease may be a physi-
ologic/genetic disorder and not suitable for the application of Koch’s postulates, or it
may be a syndrome caused by a nonliving agent (prion), which also precludes application
of the postulates.
13. Kluyver was referring to the metabolism/biochemistry common to all cellular life on the
planet, regardless of the number of cells per organism or size. The statement can be
extended to shared cellular structures as well.
14. Nitrogen compounds (NO3 , NO2 , NH3 , etc.) are often a limiting resource for growing
plants, but nitrogen gas (N2) is abundant in the air. Beijerinck’s discovery that some bac-
teria can convert nitrogen gas to nitrogen compounds is important to the cultivation of
these grains. It may be possible to (1) introduce into the soil bacteria capable of convert-
ing N2 to organic forms of nitrogen, (2) create soil conditions that promote the growth of
such bacteria, and/or (3) genetically modify crop plants with bacterial genes to convert
nitrogen gas for themselves.
CHAPTER 2 The Chemistry of Microbiology
Multiple Choice
1. c 3. c 5. b 7. a 9. a
2. d 4. c 6. c 8. a 10. c

Answers to End-of-Chapter Questions for Review 211
Fill in the Blanks
1. valence 6. hydrolysis
2. nonpolar covalent 7. exothermic
3. ATP 8. products
4. fats, waxes, amylose, glycogen 9. pH
5. functional groups 10. ribose
Visualize It!
1. Primary structure: light blue strands. Secondary structure: green α-helices, blue β-pleated
sheets (flat ribbons). The entire molecule represents tertiary structure.
2. See Figure 2.21. A carbon atom is at every angle formed by lines without a lettered des-
ignation. The amino group (NH2 ) is in the purple box, the carboxyl group is in the brown
area, and the side group is the large group in the blue box.
Short Answer
1. Three chemical bonds are polar covalent bonds (e.g., water), ionic bonds (e.g., salt), and
hydrogen bonds (e.g., in DNA). Non-polar covalent bonds (lipids) are a fourth type.
2. Five properties of water that are vital to life are that: it is cohesive, it is an excellent
solvent, it absorbs heat energy to moderate temperatures, it is liquid over a broad range
of temperature, and it participates in many chemical reactions in cells.
3. In saturated fatty acids, all the carbon bonds are linked by single bonds and are cova-
lently linked to H except on the ends. In unsaturated fatty acids, there is at least one
carbon-to-carbon double bond. In polyunsaturated fatty acids, there are several carbon-
to-carbon double bonds.
4. Atomic oxygen contains six electrons in its valence shell. Molecular oxygen forms when
two atoms of oxygen bond covalently. Each oxygen atom shares two electrons to
complete its valence shell complement of eight electrons.
5. Water is an excellent solvent because its partial charges (O– , H+ ) interact with electrically
charged molecules and dissolve them (they go into solution).
Critical Thinking
1. Eukaryotes do not metabolize D-stereoisomers of amino acids and therefore have no
enzymes to digest glycoproteins containing D-glutamic acid.
2. Dehydrogenation: de = minus, or removal; hydrogen = H; –ation = process. Therefore,
dehydrogenation means “the process of removing hydrogen.” The formation of double
bonds in a fatty acid requires the removal of hydrogens.
3. Both students are correct. H+ is the symbol for hydrogen that lacks an electron (an ion)
found in aqueous conditions. Hydrogen has only one proton and one electron and no
neutrons, so loss of an electron leaves a proton.
4. Gelatin can be changed back to a liquid because the gelatin solid is formed by relatively
weak hydrogen bonds, which can be broken by an increase in energy (heating). Heating
egg white, in contrast, involves changing covalent bonds and denaturing (unfolding)
proteins. When the egg white cools, covalent bonds reform randomly, forming

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212 MANUAL/TEST BANK FOR MICROBIOLOGY WITH DISEASES BY BODY SYSTEM, 4e
interconnections between proteins that would otherwise not share covalent bonds. Break-
ing covalent bonds requires much more energy than is required to break hydrogen bonds,
but no amount of heat will restore order to the chaos of hard-boiled egg white proteins.
5. Earth-like extraterrestrial life forms would exhibit a preference for one stereoisomer over
the other in the same manner as earthly life forms, and the sample from space would con-
tain predominantly one stereoisomeric form of amino acids. An equal, or nearly equal,
mix of stereoisomers would be consistent with nonmetabolic (nonliving) processes pro-
ducing the amino acids.
6. Baking soda (sodium bicarbonate, NaHCO3 ) will neutralize this poison.
7. Neon has two electrons in the inner shell and eight electrons in the outer cloud/shell. Ar-
gon has two in the innermost cloud/shell, eight electrons in the middle cloud, and eight
electrons in the outer cloud/shell. An eight-electron cloud is a highly stable (low-energy)
state and has no more room to add electrons. Losing an electron greatly decreases the
stability, so not sharing electrons with other atoms is a more stable (lower-energy) state
than “giving away” or “accepting” electrons. Because electron sharing (or loss) is the ba-
sis for chemical interactions, these elements do not interact with other atoms.
8. Chemists use the term organic to mean compounds that contain carbon and hydrogen,
which includes all biological molecules. Nonscientists use the term organic to mean
“from nature,” which is perceived as good or better than synthetic. There is therefore
some overlap: both groups use the term organic to mean molecules of biological origin,
but the latter position overlooks the fact that many natural processes produce toxins (e.g.,
lecithinase, botulism toxin, rattlesnake venom).
9. Hydrogen shares its single electron with carbon. The carbon shares three electrons with
nitrogen.
10. Both atoms in a triple bond have a more stable state when the valence shell is “full” with
eight electrons. Removing three electrons simultaneously (breaking the triple bond) re-
quires much more energy than removing a single electron.
11. The polar nature of the bonds between H and O and the nonlinear structure of the water
molecule mean that each H2 O molecule is usually participating in three or four hydrogen
bond pairs. Energy is required to break these bonds, and three to four bonds need to be
broken for each water molecule to escape the liquid and evaporate.
12. Magnesium hydroxide dissociates to release two OH– , whereas each molecule of HCl
dissociates to release only one H+ .
13. Linoleic acid is the least linear of the fatty acids in Table 2.4 and will best interfere with
tight packing of the fatty acids in bacterial membranes that would otherwise occur at cold
temperatures.
14. Glycine’s R group is hydrogen. Glycine therefore has two hydrogens attached to the cen-
tral carbon, and its “mirror images” are identical, that is, there are no stereoisomers.
15. Living organisms use five nucleotide bases (adenine, cytosine, guanine, thymine, and
uracil). Cells combine A, C, or T nucleotide bases with either of two different sugars (de-
oxyribose and ribose) to form nucleotides (for DNA and RNA, respectively). Thymine is
combined only with deoxyribose, and uracil is combined only with ribose; therefore,
there are eight nucleotides [(3 × 2) + 1 + 1 = 8].

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Answers to End-of-Chapter Questions for Review 213
CHAPTER 3 Cell Structure and Function
Multiple Choice
1. b 4. c 7. a 10. b 13. d
2. b 5. c 8. a 11. c 14. b
3. c 6. d 9. a 12. d 15. c
Matching
1. D, Glycocalyx
B, H, I Flagella
F, Axial filaments
H, Cilia
A, Fimbriae
C, G Pili
E, Hami
2. A, Ribosome
D, Cytoskeleton
F, Centriole
E, Nucleus
I, Mitochondrion
G, Chloroplast
C, Endoplasmic reticulum
H, Golgi body
B, Peroxisome
Visualize It!
1. a. cytoplasm—contains metabolic chemicals; b. nucleoid—site of DNA (genes);
c. glycocalyx—adhesion; d. cell wall—protects against osmotic forces; e. inclusions—
stored chemicals; f. flagellum—motility; g. cytoplasmic membrane—controls import and
export; h. nucleolus—site of RNA synthesis; i. cilium—motility; j. 80S ribosome—make
proteins; k. nuclear membrane—contains DNA (genes); l. mitochondrion—makes ATP
(energy source); m. centriole—plays a role in cell division; n. Golgi body—packages se-
cretions; o. rough endoplasmic reticulum (RER)—transports proteins; p. SER—lipid syn-
thesis; q. cytoskeleton—helps maintain cell shape
2. axial (endoflagella), peritrichous, polar (tuft), polar (single)
3. a. Chemical A enters the cell via facilitated diffusion through a protein channel, which is
likely specific for chemical A. Chemical B does not have such a route. b. At some con-
centration of chemical A, all the protein channels are filled, such that the rate of diffusion
cannot increase. c. The cell could increase the rate of diffusion of chemical A by insert-
ing more of the channel protein into the membrane. d. The rate of diffusion of chemical
B could be increased by removing chemical B from the cytoplasm at an increased rate.
This would have the effect of increasing its concentration gradient.

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214 MANUAL/TEST BANK FOR MICROBIOLOGY WITH DISEASES BY BODY SYSTEM, 4e
Short Answer
1. Diffusion is the movement (spreading) of molecules from an area of high concentration
to an area of low concentration. An example is the spreading of perfume molecules in
the air.
2. Three flagellar arrangements in prokaryotes are:
3. Cytosol is the liquid portion of cytoplasm made of water with dissolved and suspended
substances. In the cytosol are inclusions and organelles.
4. The cytoplasmic membrane is described as a fluid mosaic. It is a mosaic because its
proteins are arranged like tiles (“membrane rafts”), and it is fluid because proteins and
lipids are free to flow laterally.
5. Differences and similarities between living and nonliving things are examined in the
question of whether viruses are alive or not. Biologists agree that all living things must
exhibit growth (increase in size), reproduction (increase in number), responsiveness to
their environment, and metabolism (controlled chemical reactions producing energy and
structure).
6. Growth is an increase in size of an organism, which involves increase in cell mass,
whereas reproduction is an increase in population by sexual means or asexual means
(binary fission, budding).
7. Four similarities shared by bacterial cells and algal cells are glycocalyx, flagella, cell
wall, and cytosol. Four differences include nucleus and chloroplasts in algae, size and
components of ribosomes, and linear versus circular DNA, cell wall composition; single
versus multiple chromosomes. See also Table 3.6.
Sketch Name Description
See Figure 3.7 Polar, single Single flagellum
Polar, tuft Several flagella at one end
Peritrichous Flagella cover the surface of the cell
8. Streptococcus pyogenes Entamoeba histolytica
smaller in size larger in size
no nucleus membranous nucleus
membranous organelles absent membranous organelles
cell wall of peptidoglycan no cell wall
single chromosome multiple chromosomes
smaller 70S ribosomes in cytoplasm larger 80S ribosomes in cytoplasm
circular chromosome linear chromosomes
histones absent Histones present
9. Structure Sketch Description
Pili Figure 3.11 Long hollow tubules of pilin, used for conjugation,
longer than fimbriae
Fimbriae Figure 3.10 Bristlelike, sticky, proteinaceous, hundreds per cell
Cilia Figure 3.31
Figure 3.32
Short hairlike structures composed of tubulin protein
in a 9 + 2 arrangement. There are usually 100–1000

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Answers to End-of-Chapter Questions for Review 215
10. The ability to metabolize is unique to living things. However, if a virus is considered
nonliving, one could argue that it is involved in metabolism by taking over its host and
causing the host to make more viruses.
11. Archaeal flagella are thinner, are solid, and grow basally, whereas bacterial flagella are
thicker, are hollow, and grow at the tip. The proteins making up the flagellar subunits
differ between the two domains but are similar between species in the domains. Archaeal
flagella may have sugar molecules attached and are powered by ATP, in contrast to bac-
terial flagella, which do not have sugars attached and are powered by the flow of hydro-
gen or sodium ions across the cytoplasmic membrane at the basal body. Finally, archaeal
flagella always rotate together as a bundle. Eukaryotic flagella are hollow tubes com-
posed of tubulin in a 9 + 2 arrangement which have no hook, and do not rotate but have a
whip-like motion. Eukaryotic flagella are powered by ATP hydrolysis.
12. See also Table 3.6 on p. 87.
13. Masses of bacteria adhere to a substrate by means of sticky fimbriae and glycocalyces.
14. A molecule has difficulty moving across a cell membrane if it is too large, electrically
charged, or hydrophilic.
15. In the three types of passive transport (diffusion, facilitated diffusion, and osmosis), the
electrochemical gradient provides the source of energy rather than the cell having to ex-
pend ATP. Diffusion is the movement of small or lipid-soluble molecules down the con-
centration gradient through the spaces in the cell membrane. Facilitated diffusion occurs
when permeases provide a pathway for diffusion of large or electrically charged mole-
cules. Osmosis is specifically the diffusion of water through the membrane.
16. Active transport uses proteinaceous ports to move substances against their concentration
gradient using energy. In group translocation, the substance is chemically changed during
transport across prokaryotic membranes. Endocytosis occurs when eukaryotic cells ex-
tend the cell membrane around substances to bring them into the cell. Exocytosis occurs
when vesicles containing substances are fused with the cytoplasmic membrane, dumping
their contents outside the cell.
per cell, and they provide motility by a coordinated
wavelike motion.
Characteristic Bacteria Eukaryotes
Size 0.2–2.0 μm 10–100 μm
Presence of nucleus Absent Present
Presence of membrane-
bound organelles
Present in few Present
Structure of flagella Some have flagella composed
of flagellin, with basal body
and hook. Rotate
Some have flagella
composed of tubulin, no
hook, whip-like motion
Chemicals in cell walls Peptidoglycan Present in some,
polysaccharide
Types of ribosomes Small 70S Large 80S (small 70S in
mitochondria and
chloroplast)
Structure of
chromosomes
Usually single circular Multiple linear

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216 MANUAL/TEST BANK FOR MICROBIOLOGY WITH DISEASES BY BODY SYSTEM, 4e
17. Symports simultaneously transport two substances in the same direction through the cell
membrane, whereas antiports simultaneously transport two chemicals in opposite direc-
tions through the cell membrane.
18. The endosymbiotic theory proposes an explanation for why mitochondria and chloro-
plasts have 70S ribosomes, circular DNA, and two membranes. The theory states that
large prokaryotes internalized small aerobic prokaryotes that then lost the ability to exist
outside their host, forming the early eukaryotes. The theory does not explain the two
membranes of the nuclear envelope nor why only a few polypeptides of mitochondria
and chloroplasts are made in the organelles while the bulk of their proteins come from
nuclear DNA and cytoplasmic ribosomes.
Critical Thinking
1. A chemical that prevents Golgi function would cause a variety of problems in the human
body, all related to secretion. The respiratory tract would dry out, making breathing and
gas exchange more difficult. Digestive system problems would include loss of lubricating
mucus as well as maladsorption due to lack of digestive enzyme secretion. These would
be among the most immediate problems. Problems with hormone secretion would soon
develop. Bacteria would be unaffected because they have no Golgi bodies.
2. The nucleus and mitochondria contain DNA, so methylene blue would stain the nucleus
and mitochondria.
3. Bacterial ribosomes differ from eukaryotic ribosomes in structure and some aspects of
function. Drugs targeting those biochemical differences may be toxic to bacteria but
harmless to humans. Bacteria possess metabolic pathways not present in humans
(e.g., folic acid synthesis); drugs may inhibit such processes in bacteria without harm to
humans. Bacteria have cell walls critical to their survival whereas human cells have no
comparable structures, so drugs may target bacterial cell wall structure or synthesis with-
out affecting human cellular function or structures.
4. When the contents of the digestive system are hypertonic as a result of salt secretion,
water leaves the digestive tract cells and enters the intestinal chamber. Water leaves the
bloodstream to replace the water lost from the digestive tract cells. Continued loss of wa-
ter into the intestines “pulls” more water from the blood, which then depletes the water
stored in the tissues, possibly leading to potentially dangerous dehydration.
5. The organelle the electrode penetrated was likely the central vacuole, a prominent feature
of many plant cells.
6. As a eukaryote, Ostreococcus must have a nucleus. Since it is photosynthetic, it must
have a chloroplast.
7. Long projections from basal bodies are flagella, so this cell is probably motile. Because
the basal body is in the wall rather than within the cytoplasm, the cell is a prokaryote.
8. Positive phototaxis suggests these organisms need light, most likely for photosynthesis.
They need to be incubated in the presence of light for at least part of the day. Dark incu-
bators would not be suitable.
9. A strain of Neisseria found in a biofilm may be pathogenic. Pathogens tend to have strin-
gent environmental requirements, and the interior conditions of a biofilm may meet those
needs while other members of the biofilm community may provide nutritional needs.
10. SER (smooth endoplasmic reticulum) functions in intracellular transport and in lipid
synthesis. If it does not function, then the affected cell will be unable to make

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Answers to End-of-Chapter Questions for Review 217
cytoplasmic membranes or organelle membranes and will be hindered in transporting
substances and growth, since cell growth requires new cytoplasmic membrane.
11. The antibiotic killed the bacteria, but as the dead bacteria were degraded, the bacterial
components, including lipopolysaccharides (LPS) of the outer membrane, were released.
The lipid A component of LPS caused the body’s defense responses (fever and inflam-
mation) to intensify.
12. The hypertonic solutions have higher concentrations of solutes than the solute concentra-
tions in the bacterial and fungal cells. Because the cell membranes largely prevent the so-
lutes from entering the cells and achieving equilibrium, water tends to flow out of the
cells. The resulting dehydration brings metabolic activity to a halt, both because metabo-
lites would crystallize out of solution and because water is critical to most metabolic re-
actions.
13. Steaming mail for 30 seconds is not adequate treatment to protect people from anthrax.
Anthrax is contracted by contact with endospores, and bacterial endospores are not de-
stroyed by the relatively gentle heating of a 30-second steaming.
14. Exchange rates across the surface of a cell and surface-to-volume ratios are considered
major factors that limit cell size. Eukaryotic cells have extensive internal membranes,
particularly the endoplasmic reticulum, that function to vastly increase the functional sur-
face area of the cell. Many of the critical energy production functions (ATP synthesis,
photosynthesis) take place in the bacterial cell membrane, whereas in eukaryotes the mi-
tochondria and chloroplasts are sites of these critical functions; for this reason, surface-
to-volume ratios are not limiting for these functions in eukaryotes.
Concept Mapping
1. Gram-positive cell wall. 6. Glycan chains
2. Teichoic acids 7. N-acetylglucosamine
3. Gram-negative cell wall 8. Lipopolysaccharide (LPS)
4. Periplasm 9. Porin
5. Peptidoglycan 10. Lipid A
CHAPTER 4 Microscopy, Staining, and Classification
Multiple Choice
1. c 3. c 5. d 7. b 9. a
2. d 4. d 6. d 8. a 10. d
Fill in the Blanks
1. 600× 4. Contrast
2. heat fixation 5. negatively
3. increases, increases, more
Visualize It!
1. a. scanning electron, b. bright-field light, c. phase-contrast light, d. fluorescent light,
e. transmission electron, f. differential interference contrast (Nomarski)

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218 MANUAL/TEST BANK FOR MICROBIOLOGY WITH DISEASES BY BODY SYSTEM, 4e
2. See Figure 4.4.
a. ocular; b. body; c. arm; d. objectives; e. stage; f. condenser; g. diaphragm; h. light
source; i. course focus; j. fine focus; k. base.
Short Answer
1. Because electrons travel in smaller wavelengths than the wavelengths of visible light,
electron microscopes can magnify with greater resolution.
2. Magnification does not make things “bigger,” but it does cause the image to appear
larger.
3. Because electron microscopes require a vacuum, only dead organisms are examined.
4. The order of operations in a Gram stain is: primary stain, mordant, decolorizing agent,
counterstain.
5. Latin is used in taxonomic nomenclature because it was the scientific language of the
time of Linnaeus (the “father” of taxonomy) and because using Latin ensures that no
country has priority in the language of taxonomy.
6. A “specific epithet” is the second word in an organism’s scientific name. It is usually an
adjective, and it is written in lowercase letters. It follows the genus name, and both are
either printed in italics or underlined.
7. In the study of the taxonomic relationships among prokaryotic cells, the RNA of their
ribosomes distinguishes relationships, as in the classification of the Eukaryotes, Bacteria,
and Archaea into separate domains.
8. Electron and scanning tunneling microscopes require vacuums and use electron beams.
Organisms cannot live through the specimen preparation and procedures involved in
electron microscopy.
Critical Thinking
1. Miki was using malachite green dye, which is usually used to stain endospores.
2. The term “successfully interbreeding organisms” refers to organisms that undergo sexual
reproduction, in which haploid gametes are produced and exchanged. Bacteria and most
other microorganisms do not reproduce sexually, so the definition does not apply.
3. No, it is not logical to assume that the current taxonomy will stay the same. Our under-
standing of the interrelationships among organisms based on genetic sequences is
undergoing rapid development and is still in the early stages. Also, only a small percent-
age of microorganisms have been characterized and sequenced: as more organisms are
identified and characterized, our understanding and therefore our taxonomy are likely to
continue to develop and change.
4. Immersion oil has optical properties similar to those of the glass in slides and microscope
lenses. Light passing from the slide to the oil and into the lens is not refracted (bent), so
most of the light passing through the specimen continues into the lens, increasing the
resolution.
5. Such a microscope at 1000× magnification (10× times 100×) will be able to distinguish
between objects that are 300 nm (0.3 μm) or farther apart. Therefore, the first two objects
will be resolved, but the objects 40 nm apart will appear as a single object.
6. Both the Gram and the acid-fast staining procedures differentiate cells on the basis of dif-
ferent cell wall structures (thick versus thin peptidoglycan in Gram stains, waxy versus
nonwaxy in the acid-fast stain), and both procedures use a decolorizing step to remove

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Answers to End-of-Chapter Questions for Review 219
the initial dye from cells in which it has not been trapped, followed by a second dye to
make the decolorized cell visible. Heating followed by cooling in the acid-fast procedure
takes the place of the Gram’s iodine mordant: Heating allows the dye to penetrate the cell
wall; cooling traps the dye inside the cell wall.
7. Chondrus crispus: a curly alga with the consistency of cartilage (chondrus)
Diploccocus pneumoniae: pair of coccus, and causes pneumonia
Streptococcus pneumoniae: spherical or berry-shaped bacterium (coccus) that grows in
chains (strepto-) and causes pneumonia.
Enterococcus faecalis: spherical bacterium (coccus) from the digestive system (enteric)
found in feces.
Enterococcus faecium: spherical bacterium (coccus) from the digestive system (enteric)
found in feces; related to but not the same as E. faecalis.
Escherichia coli: bacterium named to honor Escherich and that lives in the colon.
Haemophilus influenzae: blood-loving (i.e., grows on blood agar) bacterium that
causes flu.
Homo sapiens: human species that fancies itself wise.
Isabella abbottae: not a descriptive name; indicates that Isabella Abbott is worthy of the
honor of having an organism named after her.
Pasteurella haemolytica: bacterium named to honor Pasteur and that destroys red
blood cells.
8. The bacteria were discovered by directly detecting the genetic material of the bacteria.
Comparison of the new genetic sequences with existing genetic information indicated
that the bacteria were new species. Ribosomal RNAs of prokaryotes and eukaryotes are
significantly different, so the new organisms could be identified as bacteria on the basis
of their ribosomal RNAs.
Concept Mapping
1. Iodine 4. Primary stain 7. Purple
2. Ethanol and acetone 5. Decolorizer 8. Gram-negative bacteria
3. Safranin 6. Gram-positive bacteria 9. Thin peptidoglycan layer
CHAPTER 5 Microbial Metabolism
Multiple Choice
1. c 5. a 9. a 13. a 17. a
2. a 6. c 10. c 14. a 18. c
3. c 7. b 11. d 15. a 19. a
4. a 8. d 12. d 16. c 20. c
Matching
1. C 3. E
2. B 4. A

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220 MANUAL/TEST BANK FOR MICROBIOLOGY WITH DISEASES BY BODY SYSTEM, 4e
Fill in the Blanks
1. the original reaction center chlorophyll
2. 2
3. pentose phosphate, Entner-Doudoroff
4. The Krebs cycle
5. Oxygen, ½ O 2
6. NO3– , SO4–2 , CO3–2
7. inorganic
9. chemiosmosis
10. NAD+ , FAD
Visualize It!
1. See Figure 5.12.
2. a. glycolysis (cytosol), b. electron transport (cristae), c. Kreb’s cycle (matrix)
3. Erythrose-4-phosphate, Pentose phosphate cycle; PEP, glycolysis
Short Answer
1. Amination reactions are synthetic reactions in which an amine from ammonia is added to
a metabolite. Transaminations are exchange reactions in which amine groups are moved
by transferases from one amino acid to another.
2. For anabolic reactions to occur, reactants must collide with sufficient energy for bonds to
form between them. Increasing the concentration of reactants or ambient temperatures
will cause more chemical reactions to occur; however, in living organisms neither reac-
tant concentration nor temperature is usually high enough to ensure that bonds will form.
Therefore, chemical reactions of life depend on catalysts. Organic catalysts are called en-
zymes.
3. One way in which organisms regulate metabolism is by controlling the quantity and
timing of enzyme synthesis. Also, some eukaryotic cells control some enzymatic activi-
ties by compartmentalizing enzymes inside membranes so that certain metabolic reac-
tions proceed physically separated from the rest of the cell. Enzymatic inhibitors also
may block an enzyme’s active site, preventing substrate binding. Noncompetitive
inhibitors prevent enzymatic activity by binding to an allosteric site. Cells also control
enzymatic action through feedback inhibition.
4. Binding at an allosteric site alters the shape of the active site, thereby altering the sub-
strate binding. It affects the whole pathway of enzymatic reactions in either of two ways.
In allosteric inhibition, binding of substrate is prevented, which halts any further activity.
8. Category of Enzyme Description
Hydrolase Catabolizes substrate by adding water
Isomerase Rearranges atoms
Ligase/polymerase Joins 2 molecules together
Transferase Moves functional groups
Oxidoreductase Adds or removes electrons
Lyase Splits large molecules

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Answers to End-of-Chapter Questions for Review 221
Allosteric activation, which causes the shape of the active site to change, permits sub-
strate binding, thereby activating an otherwise inactive enzyme. In the former case, the
substrate for the next step is not produced, so the pathway is shut down. In the latter case,
substrate molecules are supplied, so the metabolic pathway can proceed.
5. In negative feedback, or feedback inhibition, the end product of a series of reactions is an
allosteric inhibitor of an enzyme in an earlier part of the pathway. Because the product of
each reaction in the pathway is the substrate for the next reaction, inhibition of the first
enzyme in the series inhibits the entire pathway.
6. Microorganisms with fermentation pathways, in which organic molecules are the final
electron acceptors instead of oxygen, can colonize anaerobic environments, which are
unavailable to strictly aerobic organisms.
7. A molecule may be oxidized in one of two ways in the absence of oxygen: by losing a
single electron or by losing a hydrogen atom. A molecule other than oxygen is the elec-
tron acceptor.
8. Cyanobacteria, purple sulfur bacteria, green sulfur bacteria, green nonsulfur bacteria,
purple nonsulfur bacteria, a few protozoa, and algae are photosynthetic.
9. We breathe oxygen to be used as the final electron acceptor from the electron transport
chain, and we give off carbon dioxide from the decarboxylations of the Krebs cycle.
10. Cyanobacteria and algae capture light energy from the sun and use it to drive the
synthesis of carbohydrates from CO2 and H2 O through photosynthesis. In the dissociation
of water during photosynthesis, the molecular oxygen is a waste product.
11. E. coli uses glycolysis to split a 6-carbon glucose molecule into two 3-carbon sugar mol-
ecules, which are ultimately transformed into two molecules of pyruvic acid. The carbon
atoms in pyruvic acid may be further metabolized to carbon dioxide, or used for the syn-
thesis of other carbon compounds.
12. Yeast produce alcohol and make bread rise through the process of fermentation, the
end products of which are alcohol (ethanol) and CO2.
13. The most significant production of ATP in both prokaryotic and eukaryotic cells occurs
in the electron transport chain.
14. Vitamins are essential (“vital”) cofactors for enzymes and carrier molecules. For exam-
ple, flavoproteins contain flavin, a coenzyme derived from riboflavin. One form of flavin
is flavin mononucleotide (FMN), which is an initial carrier molecule of the electron
transport chains of the mitochondria. Some microbes can produce some cofactors and
carriers, but anything an organism cannot produce it must obtain as nutrients.
15. Glucose may act as an allosteric inhibitor of one of the enzymes that metabolize lactose.
Critical Thinking
1. The scientists could introduce Thermus and oxygen into the water so that arsenite is
oxidized to arsenate.
2. DAHAP is a substrate for three different synthetases, each of which is part of a different
metabolic pathway. As long as one pathway is active, DAHAP is required and will be
produced. Only when all three pathways are shut down by feedback inhibition will
DAHAP no longer be required and its synthesis shut down.
3. The pentose phosphate pathway is an important source of metabolic intermediates
required for amino acid and nucleotide synthesis.

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