Organic Chemistry 101: Biological Molecules
This flashcard set defines carbohydrates based on their structure and composition, typically following a C:H:O ratio of 1:2:1. It explains key structural types (aldoses vs. ketoses) and introduces common depictions of carbohydrates using Fischer and Haworth projections to represent straight-chain and ring forms, respectively.
What features define a carbohydrate?
It is an organic compound with a backbone of at least 3 carbons, typically with a C:H:O ratio of 1:2:1. Carbohydrates consist of either aldehydes or ketones with other carbons in the chain bound to hydroxyl groups.
Exceptions to the 1:2:1 ratio exist for “deoxy” sugars, in which a hydroxyl group has been replaced by a hydrogen.
Key Terms
What features define a carbohydrate?
It is an organic compound with a backbone of at least 3 carbons, typically with a C:H:O ratio of 1:2:1. Carbohydrates co...
Carbohydrate structure can be shown in many ways. What name is given to the method of depiction below?
Fischer projection - straight-chain carbohydrates are often shown in this form.
Carbohydrate structure can be shown in many ways. What name is given to the method of depiction below?
Haworth projection - carbohydrates in the ring form are often shown in this manner.
What is the difference between an aldose and a ketose?
Aldoses are sugar molecules that contain a single aldehyde group.
Briefly describe the steps for naming a straight-chain carbohydrate.
The compound is first classified as either an aldose or a ketose.
Next...
According to simple carbohydrate nomenclature, what general name can be given to this molecule?
aldopentose
This carbohydrate has an aldehyde group, which should be denoted by the pre...
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| Term | Definition |
|---|---|
What features define a carbohydrate? | It is an organic compound with a backbone of at least 3 carbons, typically with a C:H:O ratio of 1:2:1. Carbohydrates consist of either aldehydes or ketones with other carbons in the chain bound to hydroxyl groups. Exceptions to the 1:2:1 ratio exist for “deoxy” sugars, in which a hydroxyl group has been replaced by a hydrogen. |
Carbohydrate structure can be shown in many ways. What name is given to the method of depiction below? | Fischer projection - straight-chain carbohydrates are often shown in this form. On any Fischer projection, horizontal lines are considered to point out of the page (“wedges”), while vertical lines point into the page (“dashes”). Thus, this method can accurately convey stereochemistry. |
Carbohydrate structure can be shown in many ways. What name is given to the method of depiction below? | Haworth projection - carbohydrates in the ring form are often shown in this manner. The relative positions of substituents as “cis” or “trans” can be determined by whether they point upward or downward from the face of the ring. |
What is the difference between an aldose and a ketose? |
Note that both aldoses and ketoses are monosaccharides. |
Briefly describe the steps for naming a straight-chain carbohydrate. |
Note that there should be no spaces between the prefix, numerical identifier, and suffix. |
According to simple carbohydrate nomenclature, what general name can be given to this molecule? | aldopentose This carbohydrate has an aldehyde group, which should be denoted by the prefix “aldo-.” As a five-carbon sugar, it should be named using the Greek term “pent.” Finally, the “-ose” suffix identifies the molecule as a carbohydrate. |
How are cyclic carbohydrates named? | They are named based on the number of members in the ring, its two main categories are:
To denote a carbohydrate in the ring form, remove “-se” from the carbohydrate name and replace it with the suffix “-furanose” or “-pyranose,” as is appropriate. |
With regard to its cyclic structure, what general name can be given to this molecule? |
The carbohydrate has a six-membered ring form, so it is a pyranose. Five-membered rings are known as furanoses. |
What is the common name of this molecule? | glucose Glucose, a hexose, is the most common carbohydrate. Its Fischer projection can be identified by the orientation of its hydroxyl groups. From top to bottom, the -OH groups will be oriented either “right, left, right, right” (D-glucose) or “left, right, left, left” (L-glucose). |
What is the common name of this molecule? | fructose Fructose, a hexose, its Fischer projection can be identified by the orientation of its hydroxyl groups. From top to bottom, the -OH groups will be oriented either “left, right, right” (D-fructose) or “right, left, left” (L-fructose). |
What are the three main structural ways in which carbohydrates are classified? |
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What is the difference between a monosaccharide and a disaccharide? |
A polysaccharide, then, consists of more than two sugar subunits bound together. |
Name three common monosaccharides. |
Ribose and deoxyribose are also monosaccharides. Monosaccharides can be connected by glycosidic linkages to form longer sugar chains. |
Name three common disaccharides. |
In general, disaccharides consist of two sugar subunits bound by a glycosidic linkage. |
Which sugar monomers comprise sucrose, lactose, and maltose, respectively? |
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Which carbon is used to determine the absolute configuration of a carbohydrate? | The absolute configuration of a straight-chain carbohydrate is determined by the chirality of the carbon stereocenter that is farthest from the carbonyl carbon. In other words, the absolute configuration depends on the highest-numbered chiral carbon in the molecule. |
What determines whether the absolute configuration of a carbohydrate is D or L? | Any carbohydrate depicted as a Fischer projection:
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What is the absolute configuration of this carbohydrate? | TD configuration Look at the -OH on the chiral carbon farthest from the carbonyl group. Since that -OH is pointing to the right on the Fischer projection, this must be a D sugar. |
What are epimers? | These are two molecules that differ in configuration at a single chiral carbon. Epimers are a special type of diastereomer. They are especially important in relation to sugars. |
What type(s) of isomer are the carbohydrates below? | These are epimers, since they differ in configuration at only one position: the third carbon from the carbonyl. Like all epimers, these molecules are also diastereomers. |
Describe the stereochemical relationship between carbohydrates 1, 2, and 3 |
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Describe the stereochemical relationship between carbohydrates 1, 2, and 3. |
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Two carbohydrates are structurally identical but differ in configuration at three of their four chiral centers. What type(s) of isomer are these molecules? | These are diastereomers, a broad term for stereoisomers that are not enantiomers. Specifically, these molecules cannot be enantiomers since they do not have opposite configurations at all of their chiral carbons. They also are not epimers, which only differ in configuration at one position. |
For a carbohydrate to isomerize between the straight-chain and ring forms, what reaction must take place? | In the straight-chain form, the -OH on the chiral carbon farthest from the carbonyl acts as a nucleophile and attacks the carbonyl carbon. This forms a cyclic structure. In the proccess, the attacking hydroxyl loses its proton and the carbonyl oxygen becomes protonated. |
What name is given to the most oxidized carbon in the ring form of a carbohydrate? | This is called the anomeric carbon. Its stereochemical configuration is another way by which carbohydrates are classified. Abpve, the anomeric carbon is bound to a hydroxyl group and to the oxygen member of the ring. It derives from the carbonyl carbon in the straight-chain form. |
In the ring form of a carbohydrate, how can the anomeric carbon be identified? | It is the only carbon that is bound to two oxygen atoms. For this reason, all anomeric carbons are part of another functional group: acetals and hemiacetals (or ketals and hemiketals). |
What is an acetal? | It is a functional group that is derived from a carbonyl compound. It consists of two -OR groups bound to the same carbon. Conventionally, "acetal" has referred to compounds derived from aldehydes, while "ketal" refers to those derived from ketones. |
What reactants are necessary to form an acetal? | It is formed when an aldehyde is reacted with two equivalents of alcohol compounds. The -OH acts as the nucleophile and attacks the aldehyde carbon, as shown below. |
What is the difference between an acetal and a hemiacetal? |
"Hemi-" means "half," so a hemiacetal is simply a half-formed acetal. In other words, it is the product of a carbonyl compound and a single alcohol. |
What functional group is circled in the diagram below? | This is a hemiacetal. It contains a single carbon (the anomeric carbon) bound to one -OR and one -OH group. The molecule shown is cyclic glucose, a pyranose. |
What functional group is circled in the diagram below? | This is an acetal. It contains a single carbon (the anomeric carbon) bound to two -OR groups. Often, the hemiacetal functionality on a monosaccharide becomes an acetal to form a glycosidic linkage. The molecule shown is maltose, a disaccharide composed of two glucose subunits. |
What is the difference between the alpha and beta anomers of a carbohydrate? | In a Haworth projection:
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Define: mutarotation | It is the equilibration of alpha and beta anomers in solution. During this process, the optical rotation of the mixture changes. Mutarotation occurs due to the opening and closing of carbohydrate rings. When the carbohydrate opens, its carbonyl group can then be attacked from a different side, forming either the alpha or beta anomer. |
What type of linkage does the following disaccharide contain? | alpha linkage The nomenclature is determined by the anomeric carbon participating in the linkage. Here, the left carbohydrate's anomeric carbon is linked to the right carbohydrate via an oxygen atom. Since the configuration of the left anomeric carbon is alpha, this is an alpha linkage. |
What reaction is used to break the linkage between carbohydrate monomers? | Glycosidic linkages are broken via hydrolysis. As a nucleophile, water can attack the anomeric carbon in the linkage; the other carbohydrate will act as the leaving group. This reaction is a specific example of the hydrolysis of an acetal. |
Which groups on a monosaccharide can be altered by a mild oxidation reaction? | The aldehyde group on an aldose can be oxidized to a carboxylic acid, as can the terminal carbon. Tollen's reagent can only react with the aldose's aldehyde group. In contrast, nitric acid can oxidize both the aldose aldehyde and the terminal carbon to carboxylic acids. |
What product is formed by the reduction of a monosaccharide? | polyalcohol The aldehyde or ketone group will be reduced to a hydroxy group. The existing hydroxy groups will not be reduced further. |
What do Benedict's and Tollens' test detect? | These detect the presence of reducing sugars. These are carbohydrates that can act as reducing agents; in other words, they can oxidize themelves. |
What reagents are involved in Benedict's test, and what does a positive result look like? | It produces a dark red precipitate. The reagent involved is a mixture of sodium citrate, sodium carbonate, and copper sulfate pentahydrate. |
What reagents are involved in Tollens' test, and what does a positive result look like? | It yields a silver mirror-like product. The reagent involved is a mixture of ammonia and silver nitrate. |
Which components of Benedict's and Tollens' reagents directly facilitate the detection of reducing sugars? | These contain metal ions, which can be reduced by compounds that are prone to oxidation. Reducing sugars are examples of such compounds. The metal ion in Benedict's test is Cu2+, while that in Tollens' test is Ag+. |
In a ring structure, the presence of which functional group categorizes a carbohydrate as a reducing sugar? | These contains hemiacetals (or hemiketals). Since they contain an -OH group, they can further oxidize when that -OH is replaced by an -OR. Note that reducing sugars do not reduce themselves - they oxidize, thus acting as reducing agents! In a straight-chain form, aldehydes are the classic marker of a reducing sugar, as they can easily oxidize to carboxylic acids. |
Which of the molecules shown below is classified as a reducing sugar? | Molecule B is a reducing sugar. Unlike Molecule A, it contains a hemiacetal group, and is thus able to further oxidize. Molecule B is maltose, a disaccharide. Molecule A is sucrose and is also a disaccharide. |
Which new functional group is created by the reaction of a carbohydrate with acetic anhydride in pyridine? Assume the acetic anhydride is present in excess. | ester All of the carbohydrate's free hydroxyl groups are able to act as nucleophiles. They attack the carbonyl carbon of the anhydride, resulting in acylation at those positions. |